Vector Component method:

In this example we will be adding the two vectors shown below using the component method. The vectors we will be adding are displacement vectors, but the method is the same with any other type of vectors, such as velocity, acceleration, or force vectors. Let's take this all one step at a time. First, let's visualize the x-component and the y-component of d1. Here is that diagram showing the x-component in red and the y-component in green:The two components along with the original vector form a right triangle. Therefore, we can use right triangle trigonometry to find the lengths of the two components. That is, we can use the 'SOH-CAH-TOA' type of definitions for the sine, cosine, and tangent trigonometry functions.Let's find the x-component of d1. Notice that the x-component is adjacent to the angle of 34 degrees, so, we will use the cosine function since it relates an acute angle, the adjacent side to that angle, and the hypotenuse of a right triangle:Now, using trigonometry like this will not tell us the sign, (+ or -), of this component, (or any other). So, we must check the diagram for positive or negative directions. This x-component is aimed to the right, so, it is positive:(Again, remember that these calculations presented here have decimals that have been truncated. Presenting calculations to many more decimals does not help clarify methods, and, also, it violates several rules of significant digits. In other words, these calculations are approximate. The calculator below keeps many more decimal places, so, its outputs will differ slightly.)Now, let's find the y-component of d1. Notice that the y-component is opposite to the angle of 34 degrees, so, we will use the sine function since it relates an acute angle, the opposite side to that angle, and the hypotenuse of a right triangle:Again, check the diagram for positive or negative directions. The y-component aims up, so, it is positive:Here is the diagram now showing the values for the x-component and y-component of d1:Next, let's see the x-component and the y-component of d2. Here is that diagram showing the x-component in red and the y-component in green:We will now find the x-component of d2. Here the x-component is opposite the angle of 64 degrees, so we will use the sine function to find it:Check the diagram for positive or negative directions. This x-component points to the left, so, it is negative:And for our last component we will find the y-component of d2. The x-component is adjacent to the angle of 64 degrees in this diagram, so we will use the cosine function to find it:Check the diagram for positive or negative directions. This y-component is aimed up, so, it is positive:Here is the diagram showing our newly calculated values for the components of d2:Now, we must add up like components to get the components for the total displacement.To get the total x-displacement, add up all of the separate x-components:To get the total y-displacement, add up all of the separate y-components:So, when these two vectors, d1 and d2, are added, the total, or sum, has an x-component of 9.2 meters and a y-component of 30.1 meters.To get the actual 2-D total displacement, add the total x-displacement and the total y-displacement. Here is a diagram with the total x-component shown in red and the total y-component shown in green and the 2_D total shown in blue:Use the Pythagorean theorem to get the magnitude (size) of the total 2-D displacement:Use the arctangent function to get the angle:Check the diagram for NSEW notation:Therefore, our final result for the total 2-D displacement can be stated as:Here's a diagram that shows this result:Again, the component method of addition can be summarized this way:Using trigonometry, find the x-component and the y-component for each vector.